Differentials and integrals: Applications of integration
Line integral of a function
Calculate the line integral \(\displaystyle \int_C y\,\dd s\), where \(\mathcal{C}\) is the segment from \((0,1)\) to \((-2,2)\).
| \(\displaystyle \int_C y^1\,\dd s={}\) | \(\quad\text{with }\mathcal{C}=\bigl[(0,1),(-2,2)\bigr] \) |
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