Solving linear equations and inequalities: Linear inequalities in one unknown
Solving a linear inequality via equations
You can also solve a linear inequality by
- first replacing the inequality sign by an equal sign,
- then solving this equation, and
- finally, determining the sign of the inequality for point to the left and to the right of the solution of the equation.
Determine the exact solution of the inequality \[-3x -5 \le 4x -3\] via equations.
\(x \ge -{{2}\over{7}}\)
We follow the following roadmap:
- Get started with the corresponding equation \[-3x -5 = 4x -3\]
- Solve this equation:
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(-4x\) on both sides):
\(-3x -5 - 4x = 4x -3 - 4x\), which simplifies to \(-7x -5 = -3\). - Then move the terms without \(x\) to the right (by adding \(5\) both sides):
\(-7x -5 +5 = -3 +5\), which simplifies to \(-7x = 2\).- Next, divide the left- and right-hand side by the coefficient of \(x\) (which is here \(-7\)); this gives \(x = \;\frac{2}{-7}\).
- So, the solution of the equation is \(x = {-{{2}\over{7}}}\).
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(-4x\) on both sides):
- Find out whether the solutions are on the number line to the left or to the right of \(-{{2}\over{7}}\).
- First calculate the left- and right-hand sides of the inequality \(-3x -5 \le 4x -3\) when you substitute a value of \(x\) less than or equal to \(-{{2}\over{7}}\). For example, when you fill in \(x=-10\), then you get \(25 \le -43\) and this is a false statement. Any other value of \(x\) less than or equal to \(-{{2}\over{7}}\) may be used too, and you still get a false statement.
- Then calculate the left- and right-hand sides of the inequality \(-3x -5 \le 4x -3\) when you substitute a value of \(x\) greater than or equal to \(-{{2}\over{7}}\). For example, when you fill in \(x=10\), then you get \(-35 \le 37\) and this is a true statement. Any other value of \(x\) greater than or equal to \(-{{2}\over{7}}\) may be used too, and you still get a true statement.
- From these two numeric examples follows that solutions \(x\) of \(-3x -5 \le 4x -3\) must satisfy \(x \ge -{{2}\over{7}}\).
The points where the inequality holds are shown in green in the number line below. An open circle around \(x=-{{2}\over{7}}\) indicates that we are dealing with an inequality of the type \(\lt\) or \(\gt\), where in this case the point itself is not a solution. A closed circle indicates an inequality of the type \(\le\) or \(\ge\), and then the point marked on the number line is element of the solution set.
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