Complex numbers: Roots and polynomials
Extracting cube roots
Calculate exactly the principal value of \(\sqrt[3]{\tfrac{1}{2}\!\sqrt{2}+\tfrac{1}{2}\!\sqrt{2}\,\mathrm{i}}\) in polar form.
| Principal value of \(\sqrt[3]{\tfrac{1}{2}\!\sqrt{2}+\tfrac{1}{2}\!\sqrt{2}\,\mathrm{i}}\) = | (In polar notation) |
Unlock full access
