Converting a relation into a functional relationship

units
abc
abc
abc
vector
logic
function
standard

abc

↵

(

)

↑

←

↓

→

units
abc
abc
abc
vector
logic
function
standard

shift

greek

↵

(

)

↑

←

↓

→

units
abc
abc
abc
vector
logic
function
standard

shift

greek

↵

(

)

↑

←

↓

→

units
abc
abc
abc
vector
logic
function
standard

−

×∗×

√

a■

{......

[

]

∞

{}

det

(m×n)

↵

(

)

↑

←

↓

→

units
abc
abc
abc
vector
logic
function
standard

∧

⊥

∀

⊢

∅

∪

⊂

∨

⊤

∃

≠

⊨

∈

∩

⊆

∄

→

□

⊕

≥

∖

∉

⇒

⊬

⊃

↔

◇

⧆

≤

⊭

≡

{}

⇔

⊇

↵

(

)

↑

←

↓

→

units
abc
abc
abc
vector
logic
function
standard

−

×∗×

√

a■

log

sin

[

]

cos

lim

∞

[

)

≥

tan

(

]

≤

arc

{......

(

)

↵

(

)

↑

←

↓

→

units
abc
abc
abc
vector
logic
function
standard

−

×∗×

√

a■

log

sin

∧

cos

∨

≥

tan

all

≤

none

↵

(

)

↑

←

↓

→

units
abc
abc
abc
vector
logic
function
standard

°C

mol

bar

rad

units

↵

(

)

↑

←

↓

→

units
abc
abc
abc
vector
logic
function
standard

−

×∗×

√

a■

log

sin

∧

cos

∨

≥

tan

all

≤

none

↵

(

)

↑

←

↓

→

In the relation $\displaystyle y=\frac{6x}{5x-9}$ you immediately see that $y$ is a function of $x$ .
Is $x$ also a function of $y$ ? If so, what is the function definition?
In other words, can you express $x$ in $y$ , in the form $x=\mathrm{formula\;in\;} y$ .

You can also get to the solution by entering intermediate equations:
Then you see if you are still on track, but in the end you must get to the equation in the form $x=\ldots$

Functions and graphs: Relations and functions

Converting a relation into a functional relationship