Solving quadratic equations in disguise

$x$ $x$ $x$ $x$ $x$ $x$ $x$ $x$ $x$

Find the exact real solutions of the following equation.

$x^4+x^2-20=0$

Enter your answer in the form $x=a\vee x=b\ldots$ if there are two or more solutions, in the form $x=a$ if there is one solution, and the word none if there are no solutions.

About us ⋅ Help ⋅ Privacy ⋅ Terms and conditions
Copyright © 2025 Sowiso

units
abc
abc
abc
vector
logic
function
standard

7

8

9

+

4

5

6

−

1

2

3

÷

.

0

=

×∗×

√

nth root

a■

$fraction$

>

log

sin

∧

e

<

ln

cos

∨

π

≥

|

|

tan

all

≤

!

°

none

↵

backspace

(

)

C

↑

←

↓

→

x

y