Basic functions: Polynomial functions
Zeros of third degree polynomial functions
We consider the cubic polynomial \[P(x)=x^3+x^2-9\,x-9\] When we substitute \(x=-3\), it turns out that \(P(-3)=0\).
Find the other two zeros of the polynomial \(P(x)\).
Enter the answer in the form \(x=a\vee x=b\).
| Zeros of \(P(x)\) besides \(x=-3\) are: |
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