Basic functions: Polynomial functions
Zeros of third degree polynomial functions
We consider the cubic polynomial \[P(x)=x^3+6\,x^2+11\,x+6\] When we substitute \(x=-2\), it turns out that \(P(-2)=0\).
Find the other two zeros of the polynomial \(P(x)\).
Enter the answer in the form \(x=a\vee x=b\).
Zeros of \(P(x)\) besides \(x=-2\) are: |
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