Zeros of third degree polynomial functions

$x$ $x$ $x$ $x$ $x$ $x$ $x$ $x$ $x$

We consider the cubic polynomial

$P(x)=x^3-x^2-4\,x+4$ When we substitute $x=-2$ , it turns out that $P(-2)=0$ .
Find the other two zeros of the polynomial $P(x)$ .

Enter the answer in the form $x=a\vee x=b$ .

Zeros of $P(x)$ besides $x=-2$ are:

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