×
units
abc
abc
abc
vector
logic
function
standard
α
β
δ
γ
ϵ
ζ
η
θ
ι
κ
λ
μ
ν
ξ
ο
π
ρ
σ
τ
υ
φ
χ
ψ
ω
Δ
Γ
Θ
Λ
Ξ
Σ
Φ
Ψ
Ω
abc
↵
(
)
C
↑
←
↓
→
x
y
units
abc
abc
abc
vector
logic
function
standard
Q
W
E
R
T
Y
U
I
O
P
A
S
D
F
G
H
J
K
L
shift
Z
X
C
V
B
N
M
greek
↵
(
)
C
↑
←
↓
→
x
y
units
abc
abc
abc
vector
logic
function
standard
q
w
e
r
t
y
u
i
o
p
a
s
d
f
g
h
j
k
l
shift
z
x
c
v
b
n
m
greek
↵
(
)
C
↑
←
↓
→
x
y
units
abc
abc
abc
vector
logic
function
standard
7
8
9
+
4
5
6
−
1
2
3
÷
.
0
=
×
∗
×
√
a
■
{
.
.
.
.
.
.
[
,
]
i
,
∞
{
}
det
(
m
×
n
)
∙
↵
(
)
C
↑
←
↓
→
x
y
units
abc
abc
abc
vector
logic
function
standard
p
∧
⊥
φ
∀
>
=
⊢
N
∅
∪
⊂
q
∨
⊤
ψ
∃
<
≠
⊨
Z
∈
∩
⊆
∄
→
□
⊕
P
≥
∖
Q
∉
⇒
⊬
⊃
¬
↔
◇
⧆
R
≤
⊭
≡
{
}
R
⇔
⊇
↵
(
)
C
↑
←
↓
→
x
y
a
units
abc
abc
abc
vector
logic
function
standard
7
8
9
+
4
5
6
−
1
2
3
÷
.
0
=
×
∗
×
√
a
■
>
log
sin
[
,
]
<
ln
cos
lim
∞
[
,
)
≥
|
|
tan
e
,
(
,
]
≤
!
arc
π
a
{
.
.
.
.
.
.
(
,
)
↵
(
)
C
↑
←
↓
→
x
y
units
abc
abc
abc
vector
logic
function
standard
7
8
9
+
4
5
6
−
1
2
3
÷
.
0
=
×
∗
×
√
a
■
>
log
sin
∧
e
<
ln
cos
∨
π
≥
|
|
tan
all
≤
!
°
none
↵
(
)
C
↑
←
↓
→
x
y
units
abc
abc
abc
vector
logic
function
standard
m
g
s
N
K
°C
cd
J
W
C
A
V
Ω
T
H
F
dB
Hz
mol
M
eV
Pa
bar
rad
n
μ
m
c
d
da
h
k
M
G
units
↵
(
)
C
↑
←
↓
→
x
y
units
abc
abc
abc
vector
logic
function
standard
7
8
9
+
4
5
6
−
1
2
3
÷
.
0
=
×
∗
×
√
a
■
>
log
sin
∧
e
<
ln
cos
∨
π
≥
|
|
tan
all
≤
!
°
none
↵
(
)
C
↑
←
↓
→
x
y
Edit
1
2
3
4
5
6
3. Probability: Practical 3
Probability Rules
Explain in your own words the meaning of
. Indicate how you would get this value if you have the values for
and
available (no actual calculations are needed to answer this.
means the probability that
given
This can be calculated by
×
Add illustration
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×
units
abc
abc
abc
vector
logic
function
standard
7
8
9
+
4
5
6
−
1
2
3
÷
.
0
=
×
∗
×
√
a
■
>
log
sin
∧
e
<
ln
cos
∨
π
≥
|
|
tan
all
≤
!
°
none
↵
(
)
C
↑
←
↓
→
x
y