Hypothesis Test for a Proportion and Confidence Intervals

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If you compute a $92\%\,CI$ for $\pi$ using

$CI_{\pi}=\bigg(\hat{p}- z^*\cdot \sqrt{\cfrac{\pi_0\cdot(1-\pi_0)}{n}},\,\,\,\, \hat{p} + z^*\cdot \sqrt{\cfrac{\pi_0\cdot(1-\pi_0)}{n}} \bigg)$

Then there exists a direct connection between a two-sided hypothesis test for $\pi$ at the $\alpha = 0.08$ level of significance and the confidence interval:

If falls
inside
outside of
the then the null hypothesis is rejected.
If falls
inside
outside of
the then the null hypothesis is not rejected.

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