Solving linear equations and inequalities: Linear inequalities in one unknown
Solving a linear inequality via equations
You can also solve a linear inequality by
- first replacing the inequality sign by an equal sign,
- then solving this equation, and
- finally, determining the sign of the inequality for point to the left and to the right of the solution of the equation.
Determine the exact solution of the inequality \[-x -2 \ge 5x {\,+\,}5\] via equations.
\(x \le -{{7}\over{6}}\)
We follow the following roadmap:
- Get started with the corresponding equation \[-x -2 = 5x {\,+\,}5\]
- Solve this equation:
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(-5x\) on both sides):
\(-x -2 - 5x = 5x {\,+\,}5 - 5x\), which simplifies to \(-6x -2 = 5\). - Then move the terms without \(x\) to the right (by adding \(2\) both sides):
\(-6x -2 +2 = 5 +2\), which simplifies to \(-6x = 7\).- Next, divide the left- and right-hand side by the coefficient of \(x\) (which is here \(-6\)); this gives \(x = \;\frac{7}{-6}\).
- So, the solution of the equation is \(x = {-{{7}\over{6}}}\).
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(-5x\) on both sides):
- Find out whether the solutions are on the number line to the left or to the right of \(-{{7}\over{6}}\).
- First calculate the left- and right-hand sides of the inequality \(-x -2 \ge 5x {\,+\,}5\) when you substitute a value of \(x\) less than or equal to \(-{{7}\over{6}}\). For example, when you fill in \(x=-10\), then you get \(8 \ge -45\) and this is a true statement. Any other value of \(x\) less than or equal to \(-{{7}\over{6}}\) may be used too, and you still get a true statement.
- Then calculate the left- and right-hand sides of the inequality \(-x -2 \ge 5x {\,+\,}5\) when you substitute a value of \(x\) greater than or equal to \(-{{7}\over{6}}\). For example, when you fill in \(x=10\), then you get \(-12 \ge 55\) and this is a false statement. Any other value of \(x\) greater than or equal to \(-{{7}\over{6}}\) may be used too, and you still get a false statement.
- From these two numeric examples follows that solutions \(x\) of \(-x -2 \ge 5x {\,+\,}5\) must satisfy \(x \le -{{7}\over{6}}\).
The points where the inequality holds are shown in green in the number line below. An open circle around \(x=-{{7}\over{6}}\) indicates that we are dealing with an inequality of the type \(\lt\) or \(\gt\), where in this case the point itself is not a solution. A closed circle indicates an inequality of the type \(\le\) or \(\ge\), and then the point marked on the number line is element of the solution set.
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