Solving equations and inequalities: Linear inequalities in one unknown
Solving a linear inequality via equations
You can also solve a linear inequality by
- first replacing the inequality sign by an equal sign,
- then solving this equation, and
- finally, determining the sign of the inequality for point to the left and to the right of the solution of the equation.
Determine the exact solution of the inequality \[-4x -8 \gt -5x -12\] via equations.
\(x \gt -4\)
We follow the following roadmap:
- Get started with the corresponding equation \[-4x -8 = -5x -12\]
- Solve this equation:
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(5x\) on both sides):
\(-4x -8 +5x = -5x -12 +5x\), which simplifies to \(x -8 = -12\). - Then move the terms without \(x\) to the right (by adding \(8\) both sides):
\(x -8 +8 = -12 +8\), which simplifies to \(x = -4\). - So, the solution of the equation is \(x = {-4}\).
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(5x\) on both sides):
- Find out whether the solutions are on the number line to the left or to the right of \(-4\).
- First calculate the left- and right-hand sides of the inequality \(-4x -8 \gt -5x -12\) when you substitute a value of \(x\) less than \(-4\). For example, when you fill in \(x=-10\), then you get \(32 \gt 38\) and this is a false statement. Any other value of \(x\) less than \(-4\) may be used too, and you still get a false statement.
- Then calculate the left- and right-hand sides of the inequality \(-4x -8 \gt -5x -12\) when you substitute a value of \(x\) greater than \(-4\). For example, when you fill in \(x=10\), then you get \(-48 \gt -62\) and this is a true statement. Any other value of \(x\) greater than \(-4\) may be used too, and you still get a true statement.
- From these two numeric examples follows that solutions \(x\) of \(-4x -8 \gt -5x -12\) must satisfy \(x \gt -4\).
The points where the inequality holds are shown in green in the number line below. An open circle around \(x=-4\) indicates that we are dealing with an inequality of the type \(\lt\) or \(\gt\), where in this case the point itself is not a solution. A closed circle indicates an inequality of the type \(\le\) or \(\ge\), and then the point marked on the number line is element of the solution set.
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