Solving equations and inequalities: Linear inequalities in one unknown
Solving a linear inequality via equations
You can also solve a linear inequality by
- first replacing the inequality sign by an equal sign,
- then solving this equation, and
- finally, determining the sign of the inequality for point to the left and to the right of the solution of the equation.
Determine the exact solution of the inequality \[3x -7 \lt -3x {\,+\,}1\] via equations.
\(x \lt {{4}\over{3}}\)
We follow the following roadmap:
- Get started with the corresponding equation \[3x -7 = -3x {\,+\,}1\]
- Solve this equation:
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(3x\) on both sides):
\(3x -7 +3x = -3x {\,+\,}1 +3x\), which simplifies to \(6x -7 = 1\). - Then move the terms without \(x\) to the right (by adding \(7\) both sides):
\(6x -7 +7 = 1 +7\), which simplifies to \(6x = 8\).- Next, divide the left- and right-hand side by the coefficient of \(x\) (which is here \(6\)); this gives \(x = \;\frac{8}{6}\).
- So, the solution of the equation is \(x = {{{4}\over{3}}}\).
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(3x\) on both sides):
- Find out whether the solutions are on the number line to the left or to the right of \({{4}\over{3}}\).
- First calculate the left- and right-hand sides of the inequality \(3x -7 \lt -3x {\,+\,}1\) when you substitute a value of \(x\) less than \({{4}\over{3}}\). For example, when you fill in \(x=-10\), then you get \(-37 \lt 31\) and this is a true statement. Any other value of \(x\) less than \({{4}\over{3}}\) may be used too, and you still get a true statement.
- Then calculate the left- and right-hand sides of the inequality \(3x -7 \lt -3x {\,+\,}1\) when you substitute a value of \(x\) greater than \({{4}\over{3}}\). For example, when you fill in \(x=10\), then you get \(23 \lt -29\) and this is a false statement. Any other value of \(x\) greater than \({{4}\over{3}}\) may be used too, and you still get a false statement.
- From these two numeric examples follows that solutions \(x\) of \(3x -7 \lt -3x {\,+\,}1\) must satisfy \(x \lt {{4}\over{3}}\).
The points where the inequality holds are shown in green in the number line below. An open circle around \(x={{4}\over{3}}\) indicates that we are dealing with an inequality of the type \(\lt\) or \(\gt\), where in this case the point itself is not a solution. A closed circle indicates an inequality of the type \(\le\) or \(\ge\), and then the point marked on the number line is element of the solution set.
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