Solving equations and inequalities: Linear inequalities in one unknown
Solving a linear inequality via equations
You can also solve a linear inequality by
- first replacing the inequality sign by an equal sign,
- then solving this equation, and
- finally, determining the sign of the inequality for point to the left and to the right of the solution of the equation.
Determine the exact solution of the inequality \[-4x -8 \ge 2x -3\] via equations.
\(x \le -{{5}\over{6}}\)
We follow the following roadmap:
- Get started with the corresponding equation \[-4x -8 = 2x -3\]
- Solve this equation:
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(-2x\) on both sides):
\(-4x -8 - 2x = 2x -3 - 2x\), which simplifies to \(-6x -8 = -3\). - Then move the terms without \(x\) to the right (by adding \(8\) both sides):
\(-6x -8 +8 = -3 +8\), which simplifies to \(-6x = 5\).- Next, divide the left- and right-hand side by the coefficient of \(x\) (which is here \(-6\)); this gives \(x = \;\frac{5}{-6}\).
- So, the solution of the equation is \(x = {-{{5}\over{6}}}\).
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(-2x\) on both sides):
- Find out whether the solutions are on the number line to the left or to the right of \(-{{5}\over{6}}\).
- First calculate the left- and right-hand sides of the inequality \(-4x -8 \ge 2x -3\) when you substitute a value of \(x\) less than or equal to \(-{{5}\over{6}}\). For example, when you fill in \(x=-10\), then you get \(32 \ge -23\) and this is a true statement. Any other value of \(x\) less than or equal to \(-{{5}\over{6}}\) may be used too, and you still get a true statement.
- Then calculate the left- and right-hand sides of the inequality \(-4x -8 \ge 2x -3\) when you substitute a value of \(x\) greater than or equal to \(-{{5}\over{6}}\). For example, when you fill in \(x=10\), then you get \(-48 \ge 17\) and this is a false statement. Any other value of \(x\) greater than or equal to \(-{{5}\over{6}}\) may be used too, and you still get a false statement.
- From these two numeric examples follows that solutions \(x\) of \(-4x -8 \ge 2x -3\) must satisfy \(x \le -{{5}\over{6}}\).
The points where the inequality holds are shown in green in the number line below. An open circle around \(x=-{{5}\over{6}}\) indicates that we are dealing with an inequality of the type \(\lt\) or \(\gt\), where in this case the point itself is not a solution. A closed circle indicates an inequality of the type \(\le\) or \(\ge\), and then the point marked on the number line is element of the solution set.
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