Solving equations and inequalities: Linear inequalities in one unknown
Solving a linear inequality via equations
You can also solve a linear inequality by
- first replacing the inequality sign by an equal sign,
- then solving this equation, and
- finally, determining the sign of the inequality for point to the left and to the right of the solution of the equation.
Determine the exact solution of the inequality \[x + 7 \ge -2x -4\] via equations.
\(x \ge -{{11}\over{3}}\)
We follow the following roadmap:
- Get started with the corresponding equation \[x + 7 = -2x -4\]
- Solve this equation:
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(2x\) on both sides):
\(x + 7 +2x = -2x -4 +2x\), which simplifies to \(3x +7 = -4\). - Then move the terms without \(x\) to the right (by adding \(-7\) both sides):
\(3x +7 - 7 = -4 - 7\), which simplifies to \(3x = -11\).- Next, divide the left- and right-hand side by the coefficient of \(x\) (which is here \(3\)); this gives \(x = \;\frac{-11}{3}\).
- So, the solution of the equation is \(x = {-{{11}\over{3}}}\).
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(2x\) on both sides):
- Find out whether the solutions are on the number line to the left or to the right of \(-{{11}\over{3}}\).
- First calculate the left- and right-hand sides of the inequality \(x + 7 \ge -2x -4\) when you substitute a value of \(x\) less than or equal to \(-{{11}\over{3}}\). For example, when you fill in \(x=-10\), then you get \(-3 \ge 16\) and this is a false statement. Any other value of \(x\) less than or equal to \(-{{11}\over{3}}\) may be used too, and you still get a false statement.
- Then calculate the left- and right-hand sides of the inequality \(x + 7 \ge -2x -4\) when you substitute a value of \(x\) greater than or equal to \(-{{11}\over{3}}\). For example, when you fill in \(x=10\), then you get \(17 \ge -24\) and this is a true statement. Any other value of \(x\) greater than or equal to \(-{{11}\over{3}}\) may be used too, and you still get a true statement.
- From these two numeric examples follows that solutions \(x\) of \(x + 7 \ge -2x -4\) must satisfy \(x \ge -{{11}\over{3}}\).
The points where the inequality holds are shown in green in the number line below. An open circle around \(x=-{{11}\over{3}}\) indicates that we are dealing with an inequality of the type \(\lt\) or \(\gt\), where in this case the point itself is not a solution. A closed circle indicates an inequality of the type \(\le\) or \(\ge\), and then the point marked on the number line is element of the solution set.
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