Solving equations and inequalities: Linear inequalities in one unknown
Solving a linear inequality via equations
You can also solve a linear inequality by
- first replacing the inequality sign by an equal sign,
- then solving this equation, and
- finally, determining the sign of the inequality for point to the left and to the right of the solution of the equation.
Determine the exact solution of the inequality \[3x + 10 \gt -x {\,+\,}5\] via equations.
\(x \gt -{{5}\over{4}}\)
We follow the following roadmap:
- Get started with the corresponding equation \[3x + 10 = -x {\,+\,}5\]
- Solve this equation:
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(x\) on both sides):
\(3x + 10 +x = -x {\,+\,}5 +x\), which simplifies to \(4x +10 = 5\). - Then move the terms without \(x\) to the right (by adding \(-10\) both sides):
\(4x +10 - 10 = 5 - 10\), which simplifies to \(4x = -5\).- Next, divide the left- and right-hand side by the coefficient of \(x\) (which is here \(4\)); this gives \(x = \;\frac{-5}{4}\).
- So, the solution of the equation is \(x = {-{{5}\over{4}}}\).
- Get the terms with \(x\) on the left-hand side of the equation (by adding \(x\) on both sides):
- Find out whether the solutions are on the number line to the left or to the right of \(-{{5}\over{4}}\).
- First calculate the left- and right-hand sides of the inequality \(3x + 10 \gt -x {\,+\,}5\) when you substitute a value of \(x\) less than \(-{{5}\over{4}}\). For example, when you fill in \(x=-10\), then you get \(-20 \gt 15\) and this is a false statement. Any other value of \(x\) less than \(-{{5}\over{4}}\) may be used too, and you still get a false statement.
- Then calculate the left- and right-hand sides of the inequality \(3x + 10 \gt -x {\,+\,}5\) when you substitute a value of \(x\) greater than \(-{{5}\over{4}}\). For example, when you fill in \(x=10\), then you get \(40 \gt -5\) and this is a true statement. Any other value of \(x\) greater than \(-{{5}\over{4}}\) may be used too, and you still get a true statement.
- From these two numeric examples follows that solutions \(x\) of \(3x + 10 \gt -x {\,+\,}5\) must satisfy \(x \gt -{{5}\over{4}}\).
The points where the inequality holds are shown in green in the number line below. An open circle around \(x=-{{5}\over{4}}\) indicates that we are dealing with an inequality of the type \(\lt\) or \(\gt\), where in this case the point itself is not a solution. A closed circle indicates an inequality of the type \(\le\) or \(\ge\), and then the point marked on the number line is element of the solution set.
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